Physics 2A
Coefficient of Friction Lab
Objectives: To investigate the nature of the
frictional forces between a smooth metal block and a smooth flat wooden board.
Equipment: Wooden inclined plane, pulley, slotted
mass and mass holder, protractor
Inclined Plane: Whenever two bodies interact by direct
contact (touching) of their surfaces, we call the interaction forces contact
forces. The force that opposes the sliding of the bodies is known as the
friction force : the friction force is parallel to the contact surface and
always directed against the applied force. Normal (or support) force n is perpendicular to the
contact surface and is equal to the perpendicular component of the weight of
the body.
There are two different kinds of friction - static and
kinetic. Static friction fs arises when an attempt is made to slide a body at
rest. As the applied force is increased to move the body, the force of static
friction also increases. At some point the applied force becomes greater than
the maximum static friction the surface can exert and the body breaks loose.
(1)
Here ms is the coefficient of
static friction and n
is the normal force.
Now consider the following inclined plane whose
inclination angle q can be
adjusted. If a block is placed on the plane and, and the angle is slowly
increased, a point will be reached at which the block begins to slide.

At
the point when the block just slips, the maximum frictional force is exerted
and we get:
(2)
A
component of the weight of the block, mgcosq, is supported by the normal force n.
(3)
Combining equations (2) and (3) we get

The same inclined plane can be used to determine the
coefficient of kinetic friction. Decrease the angle and give the block a slight
push so that it slides down the plane at constant velocity. The static
frictional force is greater than the kinetic frictional force.
![]()
Coefficient
of Static Friction: Procedure
Table 1
|
|
1 |
2 |
3 |
4 |
|
qs |
|
|
|
|
|
ms |
|
|
|
|
|
qk |
|
|
|
|
|
mk |
|
|
|
|
2. Horizontal Plane: Place
the board in the horizontal position as given in the following figure. The following forces describe the situation:
![]()
(4)
Here T is the tension in the
string. From Eq (4) we can derive:
(5)


Measure mass m1.
Add mass m2 to the holder until the system moves. Record the
masses in Table 2. Add mass to m1 and repeat the
procedure. Calculate the coefficient of static friction for each of the cases.
Follow the procedure for Expt. 1 to calculate the coefficient of kinetic
friction.
Table
2
|
Added
Mass |
0
kg |
0.2
kg |
0.4
kg |
|
m1 |
|
|
|
|
m2 trial 1 |
|
|
|
|
m2 trial 2 |
|
|
|
|
m2 trial 3 |
|
|
|
|
Avg.
m2 |
|
|
|
|
ms |
|
|
|
|
mk |
|
|
|
Conclusion:
1)
Why
is ms
>
mk
?
2)
Does
your data confirm that the coefficients of friction are independent of normal
forces.
3)
State
in your own words what was accomplished in today’s laboratory.